The answer of the given JavaScript code might be unexpected due to the use of the post-increment operator (++). Let's break it down:

1. var x = 1;: Declares a variable x and initializes it to the value 1.
2. console.log(x+++x);: This line prints the result of the expression x+++x.

Now, let's understand how the expression x+++x is evaluated:

1. The expression starts with x, which has a value of 1.
2. The post-increment operator ++ is applied to x. This means that the value of x is first used in the expression, and then it is incremented by 1. So, x++ evaluates to 1, but x becomes 2 afterward.
3. Now, we have 1 + 2, which equals 3.

So, the output of console.log(x+++x); would be 3. However, it's important to note that the code might be considered confusing or unclear due to the way the post-increment operator is used multiple times in close proximity, which could lead to unexpected behavior if not understood properly.